Graphing Equation 3 and 4

Equation 3: d = v1 (t) + 1/2 (a) (t)2

The equation for triangle B is: (v2 - v1)(t) / 2
The equation for rectangle C is:  (v1) (t)
When you combine it together, it is: BC = ((v2-v1)(t)/2)+(v1)t
a = (v2-v1)/t
BC = [(v2-v1)/t](t2)/2 + (v1)t
BC = 1/2(a)(t)2 + (v1)t
Therefore BC is equal to equation 3


Equation 4: d = v2(t) - 1/2 (a)(t)2

The equation for triangle A is: (v2-v1)(t)/2
The equation for the entire rectangle is: (v2)t
When you subtract the triangle A from the total area, the equation is: (v2)t - (v2-v1)(t)/2
a = (v2-v1)/t
BC = (v2)t - [(v2-v1)/t] (t2)/2
BC = (v2)t - 1/2(a)(t2)
Therefore BC is also equal to equation 4